What is the difference between .@i++ and ++.@i ?

Just now when I wrote a script over discord, part of that script has shuffle algorithm
he asked, can I just change the [--.@range] into [.@range--] ?
for (.@i = 0; .@i < .@count; ++.@i) { .@rand = rand(.@range); set getelementofarray( getarg(2), .@i ), .@temparray[.@rand] + .@static; .@temparray[.@rand] = .@temparray[--.@range]; // <-- this line }
Of course the answer is NO !

The reason is because .@i++ and ++.@i has a slight difference

Short answer is:
++.@i adds the value directly
.@i++ will add the value AFTER the command execute

Long answer is:
prontera,155,185,5 script 111 1_F_MARIA,{ dispbottom (.@i++); // return 0 dispbottom (.@i); // return 1 } // === is equal to === prontera,155,183,5 script 222 1_F_MARIA,{ dispbottom (.@i); // return 0 set .@i, .@i +1; // .@i++ means run dispbottom 1st, then add the value dispbottom (.@i); // return 1 }
prontera,157,185,5 script 333 1_F_MARIA,{ dispbottom (++.@i); // return 1 dispbottom (.@i); // return 1 } // === is equal to === prontera,157,183,5 script 444 1_F_MARIA,{ set .@i, .@i +1; // ++.@i means add the value 1st, then only run dispbottom dispbottom (.@i); // return 1 dispbottom (.@i); // return 1 }


Note: when the .@i++; or ++.@i; on its own, its the same, notice the semi-colon
it only difference when put into a command, or array for example
.@array[.@i] = 1; .@i++; // is equal to .@array[.@i] = 1; ++.@i; .@array[.@i++] = 1; // is NOT equal to .@array[++.@i] = 1;


By the way, most of my script uses ++.@i in the for-loop, because Haru said so
By the way, on an unrelated note, you might want to replace .@i++ with ++.@i, since it's more efficient (the first one needs to cache the previous value of .@i to return it, while the second one doesn't)