How to compare a value within an array

setarray .@abc[0], 1,2,6,8,9,11,21,34,55,61;
how to determine the value 6 is in the array ?

I'm sure most people will loop it
for ( .@i = 0; .@i < 10; ++.@i ) if ( .@abc[.@i] == 6 ) dispbottom "OK";yeah ~ this is so basic ~

Now let me show you 3 other methods

 

Method No.1 -> use while loop

while ( .@i < 10 && .@abc[.@i] != 6 ) ++.@i; if ( .@i < 10 ) dispbottom "OK";

Method No.2 -> compare with strings

for ( .@i = 0; .@i < 10; ++.@i ) .@compare$ += "#"+ .@abc[.@i] +"#"; if ( compare( .@compare$, "#"+ 6 +"#" ) ) dispbottom "OK";

Method No.3 -> use array as pointers

for ( .@i = 0; .@i < 10; ++.@i ) .@value[.@abc[.@i]] = true; if ( .@value[6] ) dispbottom "OK";

And of course don't forget, rAthena's *countinarray

if ( countinarray(.@abc, 6) ) dispbottom "OK";OK seriously this one is cheating


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Of course all 3 methods has its own weakness

Method no.1 - it run an extra index within the while-loop
setarray .@mobid, 1001, 1002, 1004, 1005; while ( .@i < 4 && (getmonsterinfo( .@mobid[.@i], MOB_MODE ) & 1) ) ++.@i;
this one will throw error


Method no.2 - when using *countstr, countstr("#1#1#1#", "#1#"); will return 2
means, "#1#1#1#" is for *compare script command,
"#1##1##1#" is for *countstr


Method no.3 cannot use string, like IP address
.@abc["127.0.0.1"]  <-- of course doesn't work

External Links:

Help removing duplicate value from array
How to make list ID for mobs (method No. 1)
Special Party Warper (method No.2)
Please help this script about mac-address (method No.2)
getitemname2 function (method No.3)
party soul link (method No.3)